Searching element in an array : C

PROBLEM STATEMENT

Searching an Array

Write a C program to search for an element ‘a’ in the array. (Linear Search)

Input Format:

Input consists of n+2 integers. The first integer corresponds to ‘n’ , the size of the array. The next ‘n’ integers correspond to the elements in the array. The last integer corresponds to ‘a’, the element to be searched.
Assume that the maximum size of the array is 20.

Output Format:

Refer  sample output for details.

Sample Input 1:

5

2

3

6

8

1

6

Sample Output 1:

6 is present in the array

Sample Input 2:

5

2

3

6

8

1

9

Sample Output 2:

9 is not present in the array

SOLUTION

#include <stdio.h>

#include <stdlib.h>

int main(){

    int n,arr[21],search,i,flag=0;                         

    scanf("%d",&n);

//fill array with elements

    for(i=0;i<n;i++){

        scanf("%d",&arr[i]);                             

    }

//get search element

    scanf("%d",&search);

//If search element matches any of array element make flag=1 and break the loop, since //we  found the element. If not found, flag is set to 0 by default in the beginning.

    for(i=0;i<n;i++){

        if(search==arr[i]){

            flag=1;

            break;

        }

    }

//if flag =1 , we found it else we didn't. Print it using ternary operator. or if-else.

    flag==1?printf("%d is present in the array",search):printf("%d is not present in the array",search);

    return 0;

}